module LUSolve
def lusolve(a,b,ps,zero=0.0)
ps is the pivot, a vector which indicates the permutation of rows performed
a is a matrix, b is a constant vector, x is the solution vector.
Solves a*x = b for x, using LU decomposition.
def lusolve(a,b,ps,zero=0.0) prec = BigDecimal.limit(nil) n = ps.size x = [] for i in 0...n do dot = zero psin = ps[i]*n for j in 0...i do dot = a[psin+j].mult(x[j],prec) + dot end x <<= b[ps[i]] - dot end (n-1).downto(0) do |i| dot = zero psin = ps[i]*n for j in (i+1)...n do dot = a[psin+j].mult(x[j],prec) + dot end x[i] = (x[i]-dot).div(a[psin+i],prec) end x end