module Jekyll::Algolia::Indexer
def self.record_count(index)
only return the objectID and one element, to get the shortest response
Note: We'll do an empty query search, to match everything, but we'll
index - Index to check
Public: Get the number of records in an index
def self.record_count(index) index.search( '', attributesToRetrieve: 'objectID', distinct: false, hitsPerPage: 1 )['nbHits'] rescue StandardError 0 end